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  #1 (permalink)  
Old 28-Jul-2006, 08:36 AM
lmv's Avatar lmv
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ALL Records needed

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I need to have all records in the categories field show up from
[E].[LEBAEst_Cost... only 42 of the 189 are showing up. There isn't any info
in the q_sumProjPrice
for the other categories so then the info from the E].[LEBAEst_Cost
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/information-technology/13395-all-records-needed.html
doesn't show... which then returns the wrong ttls can you tell me where
to put some criteria that will make it return ALL records from the
E].[LEBAEst_Cost. I have tried changing the join but it doesn't change the
result. I need to have criteria that says to return all records in the
table... even if there is no amount in one or the other table under category.

SELECT q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/showthread.php?t=13395
q_SumProjPrice.SumOfExtendedPrice,
Sum([E].[LEBAEst_Cost]-[q_SumProjPrice].[SumOfExtendedPrice]) AS
DiffEstimatedAndExtendedPrices
FROM [EST_S-84a] AS E LEFT JOIN q_SumProjPrice ON E.Category =
q_SumProjPrice.CategoryID
WHERE (((q_SumProjPrice.ProjectID) Like [What Project ID? Ex:LEBA] &
"*"))
GROUP BY q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
q_SumProjPrice.SumOfExtendedPrice;

Thanks!!




 
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  #2 (permalink)  
Old 28-Jul-2006, 08:36 AM
BruceM's Avatar BruceM
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Posts: n/a
   
   
Re: ALL Records needed

What happens if you just leave out the WHERE (((q_SumProjPrice.ProjectID)
Like [What Project ID? Ex:LEBA] & > "*"))?

"lmv" wrote in message
news:42C27D6B-BB74-4420-98EA-0DA4B06ED5C9@microsoft.com...
>I need to have all records in the categories field show up from
> [E].[LEBAEst_Cost... only 42 of the 189 are showing up. There isn't any
> info
> in the q_sumProjPrice
> for the other categories so then the info from the E].[LEBAEst_Cost
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/showthread.php?t=13395
> doesn't show... which then returns the wrong ttls can you tell me where
> to put some criteria that will make it return ALL records from the
> E].[LEBAEst_Cost. I have tried changing the join but it doesn't change the
> result. I need to have criteria that says to return all records in the
> table... even if there is no amount in one or the other table under
> category.
>
> SELECT q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
> q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
> q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
> q_SumProjPrice.SumOfExtendedPrice,
> Sum([E].[LEBAEst_Cost]-[q_SumProjPrice].[SumOfExtendedPrice]) AS
> DiffEstimatedAndExtendedPrices
> FROM [EST_S-84a] AS E LEFT JOIN q_SumProjPrice ON E.Category =
> q_SumProjPrice.CategoryID
> WHERE (((q_SumProjPrice.ProjectID) Like [What Project ID? Ex:LEBA] &
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/showthread.php?t=13395
> "*"))
> GROUP BY q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
> q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
> q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
> q_SumProjPrice.SumOfExtendedPrice;
>
> Thanks!!
>



Reply With Quote
  #3 (permalink)  
Old 28-Jul-2006, 08:36 AM
lmv's Avatar lmv
Guest
 
Posts: n/a
   
   
Re: ALL Records needed

It still doesn't give me all of the categories... it gives me records from 3
different projects instead of filtering to the one project I want.


"BruceM" wrote:

> What happens if you just leave out the WHERE (((q_SumProjPrice.ProjectID)
> Like [What Project ID? Ex:LEBA] & > "*"))?
>
> "lmv" wrote in message
> news:42C27D6B-BB74-4420-98EA-0DA4B06ED5C9@microsoft.com...
> >I need to have all records in the categories field show up from
> > [E].[LEBAEst_Cost... only 42 of the 189 are showing up. There isn't any
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/showthread.php?t=13395
> > info
> > in the q_sumProjPrice
> > for the other categories so then the info from the E].[LEBAEst_Cost
> > doesn't show... which then returns the wrong ttls can you tell me where
> > to put some criteria that will make it return ALL records from the
> > E].[LEBAEst_Cost. I have tried changing the join but it doesn't change the
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/showthread.php?t=13395
> > result. I need to have criteria that says to return all records in the
> > table... even if there is no amount in one or the other table under
> > category.
> >
> > SELECT q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
> > q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
> > q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
> > q_SumProjPrice.SumOfExtendedPrice,
> > Sum([E].[LEBAEst_Cost]-[q_SumProjPrice].[SumOfExtendedPrice]) AS
> > DiffEstimatedAndExtendedPrices
> > FROM [EST_S-84a] AS E LEFT JOIN q_SumProjPrice ON E.Category =
> > q_SumProjPrice.CategoryID
> > WHERE (((q_SumProjPrice.ProjectID) Like [What Project ID? Ex:LEBA] &
> > "*"))
> > GROUP BY q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
> > q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
> > q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
> > q_SumProjPrice.SumOfExtendedPrice;
> >
> > Thanks!!
> >

>
>
>

Reply With Quote
  #4 (permalink)  
Old 28-Jul-2006, 08:37 AM
Allen Browne's Avatar Allen Browne
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Posts: n/a
   
   
Re: ALL Records needed

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I'm not completely clear what you want, but try:

WHERE ((q_SumProjPrice.ProjectID Is Null) OR
([What Project ID? Ex:LEBA] Is Null) OR
(q_SumProjPrice.ProjectID = [What Project ID? Ex:LEBA]))

Bruce's question was trying to clarify whether the records were actually
there to choose from, so if that suggestion does not work, go ahead and
answer his question.

--
Allen Browne - Microsoft MVP. Perth, Western Australia.
Tips for Access users - http://allenbrowne.com/tips.html
Reply to group, rather than allenbrowne at mvps dot org.

"lmv" wrote in message
news:9B5BFC52-7B26-4905-81B7-6779A7C6A099@microsoft.com...
> It still doesn't give me all of the categories... it gives me records from
> 3
> different projects instead of filtering to the one project I want.
>
>
> "BruceM" wrote:
>
>> What happens if you just leave out the WHERE (((q_SumProjPrice.ProjectID)
>> Like [What Project ID? Ex:LEBA] & > "*"))?
>>
>> "lmv" wrote in message
>> news:42C27D6B-BB74-4420-98EA-0DA4B06ED5C9@microsoft.com...
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/showthread.php?t=13395
>> >I need to have all records in the categories field show up from
>> > [E].[LEBAEst_Cost... only 42 of the 189 are showing up. There isn't any
>> > info
>> > in the q_sumProjPrice
>> > for the other categories so then the info from the E].[LEBAEst_Cost
>> > doesn't show... which then returns the wrong ttls can you tell me where
>> > to put some criteria that will make it return ALL records from the
>> > E].[LEBAEst_Cost. I have tried changing the join but it doesn't change
>> > the
>> > result. I need to have criteria that says to return all records in the
>> > table... even if there is no amount in one or the other table under
>> > category.
>> >
>> > SELECT q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
>> > q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
>> > q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
>> > q_SumProjPrice.SumOfExtendedPrice,
>> > Sum([E].[LEBAEst_Cost]-[q_SumProjPrice].[SumOfExtendedPrice]) AS
>> > DiffEstimatedAndExtendedPrices
>> > FROM [EST_S-84a] AS E LEFT JOIN q_SumProjPrice ON E.Category =
>> > q_SumProjPrice.CategoryID
>> > WHERE (((q_SumProjPrice.ProjectID) Like [What Project ID? Ex:LEBA] &
>> > "*"))
>> > GROUP BY q_SumProjPrice.CategoryID, q_SumProjPrice.CategoryName,
Reference:: Sikh Philosophy Network http://www.sikhphilosophy.net/showthread.php?t=13395
>> > q_SumProjPrice.ProjectID, q_SumProjPrice.MainCatID,
>> > q_SumProjPrice.MainCatName, E.LEBAEst_Cost,
>> > q_SumProjPrice.SumOfExtendedPrice;



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